by what least number 4320 be multiplied to obtain a number which is a perfect cube?
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heyy here is ur ans..
first take the HCF of 4320
whatever will be the factors make pairs of three bcoz in the qyestion its asking for cube.
after making three pairs one or two numbers will surely left whose three pairs could not be made
so then they will only the least no. with which 4320 be multiplied to obtain a no. which is a perfect cube.
for ex - suppose two numbers are left like 2 and 6 without pairs so multiply them n 12 will the least no. with it should be multiplied...
hope it helps u....if it did plzz mark me brainliest.....thanks...!!
first take the HCF of 4320
whatever will be the factors make pairs of three bcoz in the qyestion its asking for cube.
after making three pairs one or two numbers will surely left whose three pairs could not be made
so then they will only the least no. with which 4320 be multiplied to obtain a no. which is a perfect cube.
for ex - suppose two numbers are left like 2 and 6 without pairs so multiply them n 12 will the least no. with it should be multiplied...
hope it helps u....if it did plzz mark me brainliest.....thanks...!!
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