Question

By what least number 6663 to get a perfect square number? also find the measure of each angles ​

Answer 1

Step-by-step explanation:

ANSWER

ANSWERGiven 3332,

ANSWERGiven 3332,Resolve 3332 into prime factors, we get

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2 )

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2 )Taking squares as common from the above equation we get

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2 )Taking squares as common from the above equation we get∴ New number =(2×7×17)

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2 )Taking squares as common from the above equation we get∴ New number =(2×7×17) 2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2 )Taking squares as common from the above equation we get∴ New number =(2×7×17) 2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2 )Taking squares as common from the above equation we get∴ New number =(2×7×17) 2 =(238)

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2 )Taking squares as common from the above equation we get∴ New number =(2×7×17) 2 =(238) 2

ANSWERGiven 3332,Resolve 3332 into prime factors, we get3332=2×2×7×7×17=(2 2 ×7 2 ×17)Now to get perfect square we have to multiply the above equation by 17Then we get, 3332=2×2×7×7×17×17New number =(4×49×289)=(2 2 ×7 2 ×17 2 )Taking squares as common from the above equation we get∴ New number =(2×7×17) 2 =(238) 2