BY WHAT LEAST NUMBER
SHOULD 648 BE MULTIPLIED
TO GET A PERFECT CUBE?
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2
Answer:
648 = 2 × 2 × 2 × 3 × 3 × 3 × 3
In the prime factors, only 2 and 3 are present. 2 form a triplet (there are three 2s), while there are four 3s.To be a perfect cube, all prime factors should be in multiples of 3. Therefore, to make 648 a perfect cube, it has to be multiplied by 3 × 3 = 9 (so that there will be six 3s in total).
P.S. You can also multiply by \frac{1}{3}
3
1
, which is smaller or by \frac{1}{648}
648
1
, which is even smaller, but the officially accepted answers are integers, unless they specify otherwise
Step-by-step explanation:
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