Math, asked by samiyaashraf5401, 1 year ago

By what least number should we divide 10224 to make it perfect square

Answers

Answered by MaheswariS
6

\begin{array}{r|l}2&10224\\\cline{2-2}2&5112\\\cline{2-2}2&2556\\\cline{2-2}2&1278\\\cline{2-2}3&639\\\cline{2-2}3&213\\\cline{2-2}71&71\\\cline{2-2}&1\\\cline{2-2}\end{array}

10224=2{\times}2{\times}2{\times}2{\times}3{\times}3{\times}71

10224=2^2{\times}2^2{\times}3^2{\times}71

\text{71 does not have pair}

\therefore\textbf{We should divide the number by 71}

\textbf{to make it as a perfect square}

Find more:

What should be subtracted from the polynomial x + 2x + 8x +22x + 18 so that it is completely divisible

by x2 + 6 ?​

https://brainly.in/question/15005827

Answered by AdityaRohan
2

Answer:

10224=2×2×2×2×3×3×7110224=2{\times}2{\times}2{\times}2{\times}3{\times}3{\times}7110224=2×2×2×2×3×3×71

10224=22×22×32×7110224=2^2{\times}2^2{\times}3^2{\times}7110224=2

2

×2

2

×3

2

×71

71 does not have pair\text{71 does not have pair}71 does not have pair

∴We should divide the number by 71\therefore\textbf{We should divide the number by 71}∴We should divide the number by 71

to make it as a perfect square\textbf{to make it as a perfect square}to make it as a perfect square

Find more:

What should be subtracted from the polynomial x + 2x + 8x +22x + 18 so that it is completely divisible

by x2 + 6 ?

please mark a brainiest

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