Math, asked by eatergloo, 19 days ago

by what no. 162 and 198 is exactly divisible?​

Attachments:

Answers

Answered by dayanidhisharma19
1

Answer:

18

Step-by-step explanation:

Step 1:

Factor of a number A: a number B that when multiplied with another C produces the given number A. Both B and C are factors of A.

Step 2:

Prime Factorization of a number: finding the prime numbers that multiply together to make that number.

162 = 2 × 3^4;

162 is not a prime, is a composite number;

198 = 2 × 3^2 × 11;

198 is not a prime, is a composite number;

Step 3:

Multiply all the common prime factors, by the lowest exponents (if any).

Greatest (highest) common factor (divisor):

gcf / hcf (162; 198) = 2 × 3^2 = 18

Answered by ruchishenupcdfme
0

Answer:

Factors of 162- 2*3*3*3*3

Factors of 198- 2*3*3*11

HCF(162, 198) - 2*3*3= 18

162,198 is divisible by 18

Similar questions