Question

by what no should (-3/2)-3 be divided so that quotient is (9/16)-2

Answer 1

☆Hello friend☆

${( \frac{ - 3}{2}) }^{ - 3} \div x = { (\frac{9}{16}) }^{ - 2} \\ { (\frac{ - 2}{3} )}^{3} \times \frac{1}{x} = { (\frac{16}{9}) }^{2}$
1/x = (16/9)^2 ÷ (-2/3)^3
1/x= 256/81 × 27/-8
1/x= -32/3

3=-32 x
3/-32= x

Hope it helps

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