Question

By what no. Should (-6)^-1 be multiplied to get 9^-1?

Answer 1

Answer:

-2/3

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Answer 2

Step-by-step explanation:

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$let \: x \: be \: the \: number \: we \: have \: to \: find \\ { - 6}^{ - 1} \: \: = - \frac{1}{6} \\ now \: {9}^{ - 1} = \frac{1}{9} \\ \frac{ - 1}{6} x \: = \frac{1}{9} \\ x = \frac{ - 2}{3}$