by what number should 2^-1÷3^-1 be multiplied so that the product becomes 16
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Answer:
Let the number be ‘x’
\frac{-3}{8}\times x=\frac{-9}{16}
8
−3
×x=
16
−9
x=\frac{-9}{16}\div\frac{-3}{8}x=
16
−9
÷
8
−3
x=\frac{-9}{16}\times\frac{8}{-3}x=
16
−9
×
−3
8
x=\frac{3}{2}x=
2
3
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