by what number should 2^2/3^3 be multiplied so that the product is 1 /6
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Answer:
let the missing number = y
According to problem,
2² × 3³ × y = 1/6
4 × 27 × y = 1/6
108 × y = 1/6
y = 1/6 × 1/108
y = 1/6 × 108
y = 1/648.
∴ y = 1/648
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