by what number should (-2/3)^-3 be divided so that the quotient may be (4/27)^-2?
Answers
Answered by
12
Answer:
-91.125
Step-by-step explanation:
Let the divisor be x
ATP,
((-2/3)^-3)/x = (4/27)^-2
((-2/3)^-3)/x = (2^2/3^3)^-2
(-2/3)^-3 * 1/x = (2^2-2/3^3) = (1/3)^3
1/x = (1/3^3)/(3^-3 / -2^-3)
1/× = 3^-6/-2^-3
X = -2^-3/3^-6
X = 1/-8 * 729 = -91.125
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