Math, asked by bhuvan85, 1 year ago

by what number should (-2/3)^-3 be divided so that the quotient may be (4/27)^-2?​

Answers

Answered by sudeeptolodh786
12

Answer:

-91.125

Step-by-step explanation:

Let the divisor be x

ATP,

((-2/3)^-3)/x = (4/27)^-2

((-2/3)^-3)/x = (2^2/3^3)^-2

(-2/3)^-3 * 1/x = (2^2-2/3^3) = (1/3)^3

1/x = (1/3^3)/(3^-3 / -2^-3)

1/× = 3^-6/-2^-3

X = -2^-3/3^-6

X = 1/-8 * 729 = -91.125

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