Question

by what number should (-2/3) exponent -3 be divided so that the quotient is (9/8) exponent-2 ​

Answer 1

Let the number be '

$x$

'

So, A/Q,

$\frac{( - \frac{2}{3} )^{ - 3}}{x} = (\frac{9}{8} )^{ - 2} \\ = > x = ( - \frac{2}{3} )^{ - 3} \times (\frac{9}{8} )^{ - 2} \\ = 1 \times ( - \frac{3}{2} )^{ 3} \times 1 \times (\frac{8}{9} )^{ 2} \\ = ( - \frac{27}{8} ) \times (\frac{64}{81} ) \\ = - \frac{8}{3}$

Therefore,

$x = - \frac{8}{3}$