Question

by what number should (24)^-1 be divided so that the quotient may be equal to (4)^-1

Answer 1

let the no. be x

$\frac{ {24}^{ - 1} }{x} = {4}^{ - 1} \\ x = \frac{ {24}^{ - 1} }{ {4}^{ - 1} } \\ x = \frac{4}{24} \\ x = \frac{1}{6}$
so 1/6 is the required no.

Answer 2

24⁻¹    should be divided by   6⁻¹  so that quotient = 4⁻¹

Step-by-step explanation:

let say 24⁻¹    should be divided by  b  so that quotient = 4⁻¹

a = bq  + r

r = remainder = 0

a = 24⁻¹ = 1/24

b = ?

q = 4⁻¹ = 1/4

24⁻¹ = b4⁻¹

=> 1/24  = b(1/4)

multiplying both sides by 4

=> 4/24 = 4 b(1/4)

=> 1/6 = b

=> b = 6⁻¹

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