Math, asked by Anonymous, 6 months ago

By what number should (3/-2)^-3 be devided to get (2/3)^2

Answers

Answered by aditiyadav02
0

Answer:

x = -243/32

Step-by-step explanation:

Let the number be x.

==: (-2/3)^-3 ÷ x = (2/3)^2

==: x = (-2/3)^-3 ÷ (2/3)^2

==: x = -27/8 ÷ 4/9

==: x = -27/8 * 9/4

==: x = -243/32

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Answered by vikramsoni8784
0

Answer

-2/3 is the correct answer.

Step-by-step explanation:

divide (3/-2)^-3 by (2/3)^2.

(3/-2)^-3 will be (-2/3)^3

So, (-2/3)^3 = -8/27

and (2/3)^2 = 4/9

Therefore,

-8/27 / 4/9

= -8/27 (9/4)

=-2/3

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