By what number should (-3/2)^-3 be divided so that the quotient may be (-8/27)^-2..
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16/27 should be added
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(-3/2)¯³ ÷ x = (-8/27)¯²
(-2/3)³ ÷ x = (-27/8)² Law :- (a/b)^-m = (b/a)^m
(-2/3)³ × (-8/27)² = x
(-2/3)³ × [(-2)³/(3)³]² = x
[(-2)³/(3)³]^5 = x
[-8/27]^5 =x
(-2/3)³ ÷ x = (-27/8)² Law :- (a/b)^-m = (b/a)^m
(-2/3)³ × (-8/27)² = x
(-2/3)³ × [(-2)³/(3)³]² = x
[(-2)³/(3)³]^5 = x
[-8/27]^5 =x
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