by what number should (-3/2)^-3 be divided so that the quotient may be (-8/27)^-2
Answers
Answer:
Requirednumber(
27
−8
)
3
Step-by-step explanation:
\begin{gathered}Let \: \left(\frac{-3}{2}\right)^{-3}be \:divided\\by\: x \: so\:that \: the\: quotient \\is \:\left(\frac{-8}{27}\right)^{-2}\end{gathered}
Let(
2
−3
)
−3
bedivided
byxsothatthequotient
is(
27
−8
)
−2
\left(\frac{-3}{2}\right)^{-3}\div x = \left(\frac{-8}{27}\right)^{-2}(
2
−3
)
−3
÷x=(
27
−8
)
−2
\left(\frac{-3}{2}\right)^{-3}\div \left(\frac{-8}{27}\right)^{-2}=x(
2
−3
)
−3
÷(
27
−8
)
−2
=x
\left(\frac{-2}{3}\right)^{3}\times \left(\frac{-8}{27}\right)^{2}=x(
3
−2
)
3
×(
27
−8
)
2
=x
\left(\frac{-8}{27}\right)^{1}\times \left(\frac{-8}{27}\right)^{2}=x(
27
−8
)
1
×(
27
−8
)
2
=x
\left(\frac{-8}{27}\right)^{1+2}=x(
27
−8
)
1+2
=x
Therefore,
x=\left(\frac{-8}{27}\right)^{3}x=(
27
−8
)
3
•••♪
Answer:
Requirednumber( 27-8)3
Step-by-step explanation:
Answer:
Required\:number\:\left(\frac{-8}{27}\right)^{3}Requirednumber(
27
−8
)
3
Step-by-step explanation:
\begin{gathered}Let \: \left(\frac{-3}{2}\right)^{-3}be \:divided\\by\: x \: so\:that \: the\: quotient \\is \:\left(\frac{-8}{27}\right)^{-2}\end{gathered}
Let(
2
−3
)
−3
bedivided
byxsothatthequotient
is(
27
−8
)
−2
\left(\frac{-3}{2}\right)^{-3}\div x = \left(\frac{-8}{27}\right)^{-2}(
2
−3
)
−3
÷x=(
27
−8
)
−2
\left(\frac{-3}{2}\right)^{-3}\div \left(\frac{-8}{27}\right)^{-2}=x(
2
−3
)
−3
÷(
27
−8
)
−2
=x
\left(\frac{-2}{3}\right)^{3}\times \left(\frac{-8}{27}\right)^{2}=x(
3
−2
)
3
×(
27
−8
)
2
=x
\left(\frac{-8}{27}\right)^{1}\times \left(\frac{-8}{27}\right)^{2}=x(
27
−8
)
1
×(
27
−8
)
2
=x
\left(\frac{-8}{27}\right)^{1+2}=x(
27
−8
)
1+2
=x
Therefore,
x=\left(\frac{-8}{27}\right)^{3}x=(
27
−8
)
3
