Question

By what number should (-3/2)-3 be divided so that the quotient may be (-8/27)-2.

Answer 1

let the number be x.then,
(-3/2)-3÷x=(-8/27)-2
(-2/3)3÷x=(-27/8)2
-8/27÷x=-729/64
-8/27=-729/64x
-8/27×-64/729=x
-512/19683= x

if it will cut out then cut it through

Answer 2

number is different other all are same
By what number should (-3/2)to the power-3 be divided so that the quotient may be(4/27)to the power-2?
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(-3/2)^-3/n = (4/27)^-2
n = (-3/2)^-3/(4/27)^-2
Multiply NUM and DEN by (4/27)^2
n = (-3/2)^-3*(4/27)^2/1
Multiply NUM and DEN by (-3/2)^3

n = (4/27)^2/(-3/2)^3
n = (16/729)/(-27/8)
Invert the divisor and mutliply
n = (16/729)(-8/27)
n = -128/19683
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