By what number should (-3\2) ^-3 be multiplied , so that the product is (9/8) ^-3
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Answer:
x × ( -3/2 )^-3 = ( 9/8 )^-3
x = ( 9/8 )^-3 ÷ ( -3/2 )^-3
[ powers are same . bases should be divided ]
x = 9/8 × -2/3
x = -3/4
( -3/4 )^-3 × ( -3/2 )^-3 = ( 9/8 )^-3
hope it helps
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