Question

By what number should (-3) ^-2 be multiplied so that the product may be equal to 27​

Answer 1

${ - 3}^{ - 2} \times x = 27$

$x = \frac{27}{ { - 3}^{ - 2} }$

$x = \frac{ {3}^{3} }{ { - 3}^{ - 2} }$

$x = - (\frac{ {3}^{3} }{ {3}^{ - 2} } )$

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$

$so \: (-{3}^{3 - ( - 2)})$

$so \: answer \: is \: -{3}^{5}$

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Answer 2

Step-by-step explanation:

The number which has to be multiplied with (-3/4)^5 to obtain the product as (-64/27)^-1 is 16/9