Math, asked by PranayBhadade, 1 year ago

By what number should (3/4)^-3 be divided so that the quotient is 128?​

Answers

Answered by Mankuthemonkey01
49

Answer:

54

\rule{300}{1}

Step-by-step explanation:

To find the number that divides (\frac{3}{4})^{-3} with a quotient 128 and remainder 0.

Let's solve (\frac{3}{4} )^{-3}

(\frac{3}{4})^{-3} = (\frac{4}{3})^3\\\\\implies \frac{64}{27}\\

So, now let the number that divides 64/27 with a quotient 128 and remainder 0, be x

So, we have

\frac{64}{27} \div x = 128\\\\\implies x = 128 \times \frac{27}{64}\\\\\implies x = 2 \times 27\\\\\implies x = 54

Hence, when (3/4)^-3 is divided by 54, the quotient is 128

\rule{300}{1}

Answered by jeetemul10
5

Answer:

yes the above answer is correct pls make him brainliest...

but the real answer is 1/54

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