by what number should (_3/5)power -3 be divided so that the quotient may be (9/25)power _3
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Hi ,
( 3/5 )^-3 / x = ( 9/25 )^-3
[ since ( a/b )^-n = ( b/a )ⁿ ]
( 5/3 )³ = ( 25/9 )³ × x
[( 5/3 )/( 25/9 )]³ = x
[ ( 5 × 9 )/( 3 × 25 ) ]³ = x
( 3/5 )³ = x
Therefore ,
Required number = x = ( 3/5 )³ = 27/125
I hope this helps you.
: )
( 3/5 )^-3 / x = ( 9/25 )^-3
[ since ( a/b )^-n = ( b/a )ⁿ ]
( 5/3 )³ = ( 25/9 )³ × x
[( 5/3 )/( 25/9 )]³ = x
[ ( 5 × 9 )/( 3 × 25 ) ]³ = x
( 3/5 )³ = x
Therefore ,
Required number = x = ( 3/5 )³ = 27/125
I hope this helps you.
: )
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