By what number should -33/8be divided to get -11/2?
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\begin{gathered}\large\tt\dfrac{33}{8} \times \efrac{1}{x} = \frac{11}{2} \\\\\\\large\tt\dfrac{33}{8x} = \dfrac{11}{2} \\\\\large\tt{33 = \dfrac{11}{2} \times 8x}\\\\\large\tt{\dfrac{33 \times 2}{11} =8x}\\\\\large\tt { 6 = 8x}\\\\ \large\tt{\dfrac{6}{8} = \dfrac{3}{4}}\end{gathered}
8
33
×\efrac1x=
2
11
8x
33
=
2
11
33=
2
11
×8x
11
33×2
=8x
6=8x
8
6
=
4
3
Step-by-step explanation:
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