Math, asked by ad3782476, 11 months ago

BY WHAT NUMBER SHOULD (4/9)^-5 BE MULTIPLIED SO AS TO GET(2/3)^-2

Answers

Answered by asdfmeena2022
0
(4/9)^-5.x=(2/3)^-2
X=(2/3)^8
Answered by NAGUVEDU2016
0

Answer:

NUMBER BE X

Then

1 / (4^5 / 9^5) × X = 1 / (2^2 / 3^2)

(1 × 59049) × X / 1024 = (1 × 9) / 4

X = (1024 × 9) / (59049 × 4)

X = (256 × 1) / (6561 × 1 )

X = 256 / 6561

X = 4^4 / 9^4

X = (4/9)^4

Similar questions