BY WHAT NUMBER SHOULD (4/9)^-5 BE MULTIPLIED SO AS TO GET(2/3)^-2
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(4/9)^-5.x=(2/3)^-2
X=(2/3)^8
X=(2/3)^8
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Answer:
NUMBER BE X
Then
1 / (4^5 / 9^5) × X = 1 / (2^2 / 3^2)
(1 × 59049) × X / 1024 = (1 × 9) / 4
X = (1024 × 9) / (59049 × 4)
X = (256 × 1) / (6561 × 1 )
X = 256 / 6561
X = 4^4 / 9^4
X = (4/9)^4
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