Question

by what number should [(-5/2)^3]^-3 be multiplied to get (-2/5)^5

Answer 1

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Here is your answer.

Let the number is x

ATQ
$x \times (( - \frac{5}{2} ) {}^{3} ) {}^{ - 3} = ( - \frac{2}{5} ) {}^{5} \\ \\ x \times ( - \frac{5}{2} ) {}^{ - 9} = ( - \frac{2}{5} ) {}^{5} \\ \\ x = \frac{( - \frac{2}{5} ) {}^{5} }{( - \frac{5}{2}) {}^{ - 9} } \\ \\ x = ( - \frac{2}{5} ) {}^{5} \times ( - \frac{2}{5} ) {}^{ - 9} \\ \\ x = ( - \frac{2}{5} ) {}^{5 - 9} \\ \\ x = ( - \frac{2}{5}) {}^{ - 4} \\ \\ x = ( - \frac{5}{2} ) {}^{4}$
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Answer 2

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$<i><font face= Copper black size=4 color=red><h3><marquee>$
Here is your answer

Let the number is x

So,

$x \times ( - \frac{5}{2} ) {}^{3 \times - 3} = ( - \frac{2}{5} ) {}^{5} \\ \\ x \times ( - \frac{5}{2} ) { }^{ - 9} = ( - \frac{2}{5} ) {}^{5} \\ \\ x = ( - \frac{2}{5} ) {}^{5} \times ( - \frac{2}{5} ) {}^{ - 9} \\ \\ x = ( - \frac{2}{5} ) {}^{5 - 9} \\ \\ x = ( - \frac{2}{5} ) {}^{ - 4} \\ \\ x = ( - \frac{5}{2} ) {}^{4}$

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