Question

by what number should (-6)^-1 be multiplied so that the product becomes 9 ^ -1

Answer 1

let required number be x, 

(-6)^-1 × x = 9^-1

-x/6 = 1/9 

-x = 6/9 

x = -2/3
 


-2/3 is the required number 



i  hope this will help you


(-:

Answer 2

Answer:

$\frac{-2}{3} \text{ should be multiplied so that product becomes }9^{-1}$

Step-by-step explanation:

$\text{Given the number }(-6)^{-1}$

$\text}{we have to find the number by which the given number should be multiplied so that product becomes }9^{-1}$

Let the number be x

$(-6)^{-1}\times x=9^{-1}$

$-\frac{1}{6}\times x =\frac{1}{9}$

$\text{Multiply by (-6) both sides, we get }$

$x=\frac{1}{9}\times (-6)=\frac{-2}{3}$

$\text{Hence, }\frac{-2}{3} \text{ should be multiplied so that product becomes }9^{-1}$