Question

by what number should (-8)^-1 be multiplied to get 10^-1 ? please explain it clearly and fast​

Answer 1

Answer:

33/21

Step-by-step explanation:

(64-1)×x=(100-1)

63×x=99

x=99/63

x=33/21

Answer 2

Answer:

It should be multiplied by -8/10

Step-by-step explanation:

let the no. be n

A/Q,

(-8)^-1 × n = (10)^-1

we know that,

for any no x,

(x)^-1 = 1/x

=> (-1/8) × n = 1/10

=> n = 1/10 ÷ (-1/8)

=> n = 1/10 × (-8/1)

=> n = -8/10