Question

By what number should (-9)^-1 be divided so that the quotient is (18)^-1

Answer 1

Answer:

2-¹ or, ½

Step-by-step explanation:

Let the number be X

=> (-9)-¹ ÷ X = (18)-¹

=> -⅑ ÷ X = 1/18

=> 1/18 × X = -⅑

=> X = -⅑ ÷ 1/18

=>X = -⅑ × 18

=> X = 2-¹ = ½

hope it is helpful

Answer 2

(-9)⁻¹ should be divided by 1/-162 to get -18 as the quotient.

GIVEN

Dividend = (-9)⁻¹

Quotient = (18)⁻¹

TO FIND

DIVISOR

SOLUTION

We can simply solve the above problem as follows -

We know that when a number 'n' is raised to the power of - 1 then,

n⁻¹ = 1/n

So,

-9⁻¹ = 1/-9

and,

18 ⁻¹ = 1/18

Now,

Let the divisor be x

So,

$\frac{1}{ - 9} \div x = \frac{1}{18}$

we can also write it as,

$\frac{1}{ - 9} \div \frac{x}{1} = - 18$

We know that to divide two fractions the first fraction is multiplied by the reciprocal of the second fraction

Therefore,

$\frac{1}{ - 9} \times \frac{1}{x} = - 18$

Solving for x

$\frac{1}{ - 9x} = - 18$

$1 = - 18 \times 9x$

$x = \frac{1}{ - 162}$

Hence, (-9)⁻¹ should be divided by 1/-162 to get -18 as the quotient.

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