By what number should each of the following numbers be multiplied to get a perfect square in each case? Also, find the number whose square is the new number. 661500
Answers
Answered by
1
Answer:
156 We are going to find prime factors of 4056 4056=2×2028
=2×2×1014
=2×2×2×507
=2×2×2×3×169 =
2×2×2×3×13×13
Now, we are going to make a group of equal number.
=(2×2)×(13×13)×2×3
By observation, 2 and 3 prime factor left out. So, multiply by 6
we get, 4056×6 =(2×2)×(13×13)×(2×2)(3×3) 24336=(2×2×3×13)×(2×2×3×13)
=(156)×(156)
=(156)2 ∴
To make perfect square we have to multiplied 4056 by 6.
Similar questions