Question

By what number should minus 3 by 2 whole power minus 3 be divided so that the quotient may be 9 by 4 wholepower minus 2

Answer 1

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Here is your answer.

Let the number is x
ATQ
$\frac{( \frac{ - 3}{2}) {}^{ - 3} }{x} = (\frac{9}{4} ) {}^{ - 2} \\ \\ ( \frac{ 2}{ - 3} ) {}^{3} \times \frac{1}{x} = ( \frac{4}{9} ) {}^{2} \\ \\ ( \frac{8}{ - 27} ) \times \frac{1}{x} = \frac{16}{81} \\ \\ x = \frac{8 \times 81}{ - 27 \times 16} \\ \\ x = \frac{3}{ - 2} \\ \\ x = - \frac{3}{2}$
Therefore the number is -3/2


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Answer 2

Hi friends

Here is your answer.

Let the number is x

ATQ
$\frac{( \frac{ - 3}{2}) {}^{ - 3} }{x} = (\frac{9}{4} ) {}^{ - 2} \\ \\ ( \frac{ 2}{ - 3} ) {}^{3} \times \frac{1}{x} = ( \frac{4}{9} ) {}^{2} \\ \\ ( \frac{8}{ - 27} ) \times \frac{1}{x} = \frac{16}{81} \\ \\ x = \frac{8 \times 81}{ - 27 \times 16} \\ \\ x = \frac{3}{ - 2} \\ \\ x = - \frac{3}{2}$


Hence the number is
$= - \frac{3}{2}$

Hope it helps you

@ MSD