by what number should minus 3 upon 2 raise to power minus 3 divided so that the quotient maybe -8/27 raise to power -2
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Step-by-step explanation:
the number be 'p'
(4/2)^-3/(p)=(-8/27)^-2
(4/2)^-3=(-8/27)^-2×p
=(-8/27)^-2 p
therefore,
(4/3)^-3/(-8/27)^-2=p
(3/4)^3/(27/-8)^2=p
( 27/64)/(729/16)=p
(27/64)×(16/729)=p
(3√27/64)×(3√16/729)=3√p ....
{cube-rooting on both sides}
(3√27/64)×(3√8×8/729)=3√p
(3/4)×[(2×2)/9)=3√p
(3/4)×(4/9)=3√p
(3×4/4×9)=3√p
(12/36)=3√p
(1/3)=3√p
(1/3)^3=(3√p)^3 ......
{ taking cube on both side}
(1/3)^3=p
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