Question

by what number should we multiply - 1/6 so that the product is -23/9

Answer 1

$\bf{\large{\underline{\underline{Answer:-}}}}$

The required number is 46/3

$\bf{\large{\underline{\underline{Explanation:-}}}}$

Let the number be x

Another number = $\sf{- \dfrac{1}{6} }$

Product of two numbers = $\sf{- \dfrac{23}{9} }$

According to the question :-

$\tt{\dfrac{-1}{6} \times x = \dfrac{-23}{9}}$

$\tt{\dfrac{ - x}{6}=\dfrac{ - 23}{9}}$

$\tt{-x = \dfrac{- l23 \times 6}{9}}$

$\tt{- x = \dfrac{ - 23 \times 2}{3}}$

$\tt{- x = - \dfrac{46}{3}}$

$\tt{x = - \left( - \frac{46}{3}\right)}$

$\tt{x= \dfrac{46}{3}}$

$\bf{\large{\underline{\underline{Verification :-}}}}$

$\dfrac{ - 1}{6} \times \dfrac{46}{3} = \dfrac{ - 23}{9} \\ \\ \frac{ - 1}{3} \times \dfrac{23}{3} = \dfrac{ - 23}{9} \\ \\ \dfrac{ - 23}{9} = \dfrac{ - 23}{9}$

Therefore the required number is 46/3