Question

By what per cent is B's weight more than that of A, if A’s weight is 25% less than that of B?
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Answer 1

To Find:-

• By what per cent is B's weight more than that of A .............(?)

Solution:-

Given that, the weight of A is 25% less than B

Let the total weight be 100

Step-by-step explanation:-

∴ ( 100 - 25 )% of B

= 75% of B

Now,

⟹ A/100 × B

⟹ A = 75/100 × B ........... equation 1

Therefore, from this we get,

⟹ B = 100/75 × A ............ equation 2

Now, in order to find out the per cent by which B is more than A we need to find,

( B - A ) / A

Now, Let's substract equation 1 from equation 2

⟹ B - A = 100/75 × A - 75/100 × B ..... equation 3

Finally, Let's substitute the value of B from 2

⟹ B - A = 100/75 × A - A

⟹ B - A = ( 100A - 75A ) / 75

⟹ B - A = 25A/75

⟹ ( B - A ) / A = 1/3

Now, Converting 1/3 into percentage

= 1/3 × 100

= 33.33≈ %

Required Answer:-

• 33.33% is B's weight more than that of A.