Question

By what per cent is b's weight more than that of a, if a's weight is 25% less than that of b

Answer 1

a= 75b/100

b= 100a/75

b-a = 25a/75

b-a/a = 1/3
(b-a)100/a = 33percent

Answer 2

Answer: The weight of b is more than weight of a by  $33\dfrac{1}{3} \%$

Step-by-step explanation:

Let the weight of b = 100

weight of a is 25% less than weight of b

therefore weight of a is $100- 25\5 \text { of }100 = 100- \dfrac{25}{100} \times 100= 75$

b weight is more than a weight by 25

weight percentage  = $\dfrac{25}{75} \times 100= 33\dfrac{1}{3} \%$

Hence, the weight of b is more than weight of a by  $33\dfrac{1}{3} \%$