Question

by what percent is B's weight more than that of A,if A's weight is 25% less than that of B?
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Answer 1

B's weight is $33\dfrac{1}{3}\%$ more than that of A.

Step-by-step explanation:

Since we have given that

A's weight is 25% less than that of B.

Let the weight of B be 100

Let the weight of A be 75

So, we need to find the percentage by which B's weight is more than that of A.

So, it becomes,

$\dfrac{Difference}{A's\ weight}\times 100\\\\=\dfrac{25}{75}\times 100\\\\=\dfrac{100}{3}\\\\=33\dfrac{1}{3}\%$

Hence, B's weight is $33\dfrac{1}{3}\%$ more than that of A.

# learn more:

By what percent is B's weight more than that of A,if A's weight is 25% less than that of B?

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