By what Percent will the illumination of the damp decrease if the current Drop by 20 percent
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2
Answer:
36
Explanation:
E=P.T
E=VIT
E=I^2RT
E proportional to I^2
so
E1/E2=I1^2/(80^2 I2^2/100^2)
on solving E2=80^2E1/100^2
which comes 64/100
so its 36% less
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