Question

By what percentage momentum of a ball will
decrease if its kinetic energy decreases to 49%
of initial.​

Answer 1

Answer:

Explanation:

K= p /2m

p= square root.2mK

Decrease in Kinetic energy= 49% of K

i.e 49/100 * K = 0.49K

Final K.E , K'= 0.51

Final momentum, p' = square rt. 2mK' = sqr. rt. 2m x 0.51K

= square root 0.51*2mK

increase in p

p-p'/p x 100

insert the values, you will get answer