by what smallest number should 19652 be multiplied so that the product becomes a perfect cube? also, find the cube root of the product.
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We have,
19652=2×2×17×17×17
After grouping the prime factors in triplets, it’s seen that factors 2×2 are left ungrouped in 3’s.
19652=2×2×(17×17×17)
So, in order to complete it in a triplet one more 2 is needed.
Thus, the smallest number which should be multiplied to 19652 in order to make it a perfect cube is 2.
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