Question

by which no. 1188 must be divided to get its quotient is a perfect cube​

Answer 1

Answer:

44

Explanation:

we should first prime factorise 1188

THe prime factors are 3,3,3,2,2,11

now form groups like  333 we must form groups with three same nos but the number 2,11,11 are missing to make a group for 2 and 11 so we must divide extra nos that are 2,2,11    1188 divided by 2x2x11 = 27  final answer is 27 which is 3 cube

       

Answer 2

Answer:

44

Explanation:

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