Question

by which number should minus 8 to the power minus 1 be multiplied so that the product is equal to 10 to the power minus 1 ​

Answer 1

Answer:

$let \: the \: no \: be \: x \\ - {8}^{ - 1} \times x = {10}^{ - 1} \\ ( { \frac{ - 1}{8} )}^{1} \times x = \frac{1}{10} \\ x = \frac{1}{10} \div - \frac{ - 1}{8} \\ x = \frac{1}{10} \times - 8 \\ x = \frac{ - 4}{5}$

therefore it should be multiplied by -4/5

Answer 2

Answer:

gere is your answer

Step-by-step explanation:

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