Math, asked by narusarshi2345, 7 months ago

by which rational number -3/5 be divided to get -2/3 ?​

Answers

Answered by Anonymous
4

\red{\color{white}{\fcolorbox{cyan}{black}{Answer:-}}}

Let the rational number be x.

{\sf{ \frac{ - 3}{5} \div x  =  \frac{ - 2}{3}}}  \\ \\  {\implies} {\sf{\frac{ - 3}{5}  \times  \frac{1}{x}  =  \frac{ - 2}{3}}}  \\ \\   {\implies} {\sf{ \frac{1}{x}  =  \frac{ - 2}{3}  \times  \frac{5}{ - 3}}}  \\ \\   {\implies} {\sf{ \frac{1}{x}  =  \frac{10}{9}}}  \\ \\   {\implies}{\sf{ x =  \frac{9}{10}}}  \\ \\   { \therefore} \: {\sf{\red{x =  \frac{9}{10}}}}

So,  \frac{ - 3}{5} should be divided by  \frac{ 9}{10} to get  \frac{ - 2}{3}.

Answered by Sudhir1188
4

ANSWER:

  • Required rational number = 9/10

GIVEN:

  • One rational number = -3/5
  • Resultant rational number = -2/3.

TO FIND:

  • Other rational number.

SOLUTION:

Let x be another rational number.

 \implies \:  \dfrac{ - 3}{5}  \div x =  \dfrac{ - 2}{3}  \\  \\  \implies \:  \dfrac{ - 3}{5x}  =  \dfrac{ - 2}{3}  \\  \\  \implies \: 5x \times ( - 2) = ( -3) \times 3 \\  \implies \:  - 10x =  - 9 \\  \implies \: 10x = 9 \\   \implies \: x =  \dfrac{9}{10}

Required rational number = 9/10

NOTE:

  • This type of questions can be solved by first supposing a rational be x or any other variables.
  • Then simply it and get the value of variable.
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