By which smallest natural number should 594 be divided so that quotient is a perfect cube :
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Step-by-step explanation:
Correct answer is 297.
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Answered by
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Answer:
Correct option is
A
44
Prime factorising 1188, we get,
1188=2×2×3×3×3×11
=2
2
×3
3
×11.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 2's is 2, number of 3's is 3 and number of 11's is 1.
So we need to divide 2
2
and 11 from the factorization to make 1188 a perfect cube.
Hence, the smallest number by which 1188 must be divided to obtain a perfect cube is 2
2
×11=44
Step-by-step explanation:
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