Question

by which smallest number 2624 should be divided so as the quotient could become a perfect cube .
find the cube root of that quotient​

Answer 1

Answer:

$2624 \div 41 = 64$

& Cube root of 64 is 4

❤️HOPE IT IS HELPFUL TO U❤️

Answer 2

$\rule{200}3$

$\color{red}\huge{\underline{\underline{\mathfrak{Question:-}}}}$

By which smallest number 2624 should be divided so as the quotient could become a perfect cube?

Also find the cube root of that quotient.

$\rule{200}3$

$\color{blue}\huge{\underline{\underline{\mathfrak{Answer:-}}}}$

${\bold{\blue{\text{41 is the answer to part 1}}}}$

${\bold{\blue{\text{4 is the answer to part 2}}}}$

$\rule{200}3$

$\color{orange}\huge{\underline{\underline{\mathfrak{Verification:-}}}}$

${\bold{\orange{\text{2624 \div 41}}}}$

${\bold{\orange{\text{64}}}}$

$\rule{200}3$

${\bold{\red{\text{Answer to part 2}}}}$

${\bold{\pink{\text{Quotient we got = 64}}}}$

$\sqrt[3]{64}$=$4$

Hope it helps.