Math, asked by parmjeetdeora40400, 11 months ago

by which smallest number 5400 must be multiplied to make it a perfect cube .
please explain it with steps ( prime factorisation)
don't post irrelevant answers​

Answers

Answered by xxiTzSiLeNtKiLlErxx
2

5400 = 9 x 6 x 100

= 27 x 2 x 5 x 5 x 4

= 27 x 5^2 x 2^2

= 2^3 x 3^3 x 5^2

, 27 is a cube, therefore, 5 x 5400 is a cube, i.e. 27,000. Therefore, the required number is 5 to get a perfect cube. 5400= (2*2*2)*(3*3*3)*(5*5). If 5 is multiplied,it becomes a perfect cube.

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Answered by hemant1810
1

5400 = 9 x 6 x 100

= 27 x 2 x 5 x 5 x 4

= 27 x 5^2 x 2^2

= 2^3 x 3^3 x 5^2

, 27 is a cube, therefore, 5 x 5400 is a cube, i.e. 27,000. Therefore, the required number is 5 to get a perfect cube. 5400= (2*2*2)*(3*3*3)*(5*5). If 5 is multiplied,it becomes a perfect cube.

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