CBSE BOARD XII, asked by siyachandervans4276, 5 hours ago

Bypass capacitor cs is a common source amplfier if gm= 1mA/v and low 3-dB freq in 100Hz

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Answered by sril1983
0

Answer:The value of the bypass capacitor whose g and frequency values are given, is 10μF. This is because the capacitance value Cs is obtained by dividing the trans-conductance value by the frequency value.

This implies, Cs = (g/f) = (0.001/100) = 10^(-5) F = 10 * 10^(-6) F = 10μF.

Explanation:

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