Question

BYTUS
Given 15 cot A=8, find sina
and sec A.​

Answer 1

Step-by-step explanation:

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Answer 2

$\huge\bold\black{ question }$

15cot A= 8

✿solution✿☘️

15cot = 8

$cot = \frac{8}{15} = \frac{b}{p}$

by Pythagoras theorem

$h ^{2} = b ^{2} + p ^{2} \\ \\ h ^{2} = 8 ^{2} + 15^{2} \\ \: \: \: \: \: \: = 64 + 225 \\ \: \: \: \: \: = 289$

$h ^{2} = 289 \\ h = 17$

now ;

B=8 , P= 15 , H= 17

$sin \: a \: = \frac{p}{h} = \frac{15}{17}$

$sec \: a \: = \frac{h}{b} = \frac{17}{8}$

hope it's helpful for uh ☘️