Math, asked by nellronaurelia549, 5 hours ago

C(0)=12(0)0²+5=0
$c(0) = 12(0) >0 {}^{2} + 5 = 0$

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Answered by alltype302

1

Answer:

C(0)=12(0)0²+5=0

$c(0) = 12(0) >0 {}^{2} + 5 = 0$

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