Chemistry, asked by sofya123khan, 1 year ago

c. 0.40 0.40 1.40 1.40
d. 0.40 0.40 0.40 0.40
On taking 60.0 g CH2COOH and 46.0 g CH2CH2OH in a 5 L flask in the presence
of H20* (catalyst), at 298 K 44.0 g of CH3COOC2H5 is formed at equilibrium.
If amount of CH3COOHis doubled without affecting amount of CH2CH2OH, then
CH3COOC2H5 formed is
a. 20.33 g
b. 22.0 g
C. 44.0g
d. 58.66 g​

Answers

Answered by rg123edit
0

Explanation:

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