Question

C= 1.
7. Find the area of a rectangle whose sides are 2a and 3a.​

Answer 1

Answer:

According to question

sides of rectangle

2a , 2a , 3a , 3a

we know that,

Area of rectangle= length X breath _______equation (1)

so,

let length = 3a

breath = 2a

but the value of length and breath in equation (1)

therefore,

Area of rectangle = 3a X 2a

= 6a²

Step-by-step explanation:

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Answer 2

${\purple{\underline{\underline{\bf{\pink{Solution:-}}}}}}$

$\mathfrak{\underline{AnswEr:-}}$

• The area of rectangle = 6a²

$\mathfrak{\underline{Given:-}}$

• The sides of a rectangle is 2a and 3a.

$\mathfrak{\underline{Need\:To\: Find:-}}$

• The area of a rectangle = ?

${\purple{\underline{\underline{\bf{\pink{Explanation:-}}}}}}$

Let,

• The length of rectangle be 3a.
• And, the breadth of rectangle be 2a.

$\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}$

$\bigstar{\underline{\boxed{\sf\purple{Area\:of\: rectangle = Length \times Breadth}}}}$

$\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}$

$\longrightarrow \sf {Area\: of \:rectangle = 3a \times 2a}$

$\longrightarrow \sf {Area\: of \:rectangle = 6a^2}$

$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

• The area of rectangle is 6a².

$\rule{200}{2}$