Question

C
1 A 60 kg skater and an 80 kg
skater standing in the middle of
an ice rink, push each other away.

What can be said about:

a the force they exert on each
other when they push apart?

b the momentum each skater
has just after they separate?

c each of their velocities after they separate?

d their total momentum just after they separate?

Answer 1

HEY RAYHAN!!!! LONG TIMEE ANYWAYS:

a) They exert equal & opposite push forces on one another, forming an action-reaction pair under Newton's 3rd Law.

b) Pushing from rest, hence equal & opposite momenta: p (80) = - p (60).

c) 80v = -60v* => v = -(3/4)v*. So 80 kg travels at 3/4 speed (velocity mag) of 60 kg, their velocities oppose in direction.

d) Total p (before) = Total p (after) = 0 kg ms^-1. i.e) momentum conserved in the absence of external forces.

Answer 2

Answer: 7.5 m/s west

Explanation: