Question

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C
10. In the given figure, side BC of AABC is
bisected at D and O is any point on AD. BO
and CO produced meet AC and AB at E and
F respectively, and AD is produced to X so
that D is the midpoint of OX. Prove that
AO: AX = AF: AB and show that EF || BC.
F
B
C
D
Х​

Answer 1

Answer:

The side BC of a triangle ABC is bisected at D; O is any point in AD. BO and CO produced meet AC and AB in E and F respectively and AD is produced to X, So that D is the midpoint of OX. Prove that AO: AX = AF : AB and show that FE || BC. Given: D is the mid point of BC as well as OX.