Math, asked by amardeepgautam9, 1 month ago

(C) 10 Krishna can do a work in 10 days while Mohan can do the same work in 20 days. They started work together. After 3 days Krishna left the work and Mohan completed it. For how many days Mohan worked alone more than the number of days required when both worked together? 1 (a) 4. (6) 31 3 4 2 ) (d) 3 3 cr​

Answers

Answered by SATHWIK3633l
0

Answer:

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Answered by shanukumar1512
0

Answer:

Krishna's efficiency = 10%

Mohan's efficiency = 5%

Work done by Krishana and mohan together in 3 days = 15 x 3 = 45%

Now, number of days in which B completed rest (55%) work alone = 55/5 = 11

Total No. of days in which B worked = 3 + 11 = 14

Now No. of days required by B, when A and B both worked together = 100/15 = 62/3

∴ Required difference in No. of days = (11) - (62/3)

= 13/3 = 4 1/3 days

Step-by-step explanation:

MARK. AS BRILLIANT

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